QQuestion
How many grams of CaCO₃ will react with excess of dilute HCl to produce 66 g of CO₂?
[Ca = 40, C = 12, O = 16]
✓Answer
Molar Mass of CO₂ = 12 + (16 × 2) = 44 g
Molar Mass of CaCO₃ = 40 + 12 + (16 × 3) = 100 g
Balanced Chemical Equation:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
100 g 44 g
From the balanced equation,
100 g of CaCO₃ produces 44 g of CO₂.
Therefore, Mass of CaCO₃ required to produce 66 g of CO₂
= \frac{100 \times 66}{44}
= 150 g
Hence, 150 g of CaCO₃ is required to produce 66 g of CO₂.
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