QQuestion
What will be the volume of 8 g of H₂ gas (H = 1) at a pressure of 4 atmospheres and a temperature of 27°C?
[R = 0.082 litre atmosphere mole⁻¹ K⁻¹]
✓Answer
Mass of H₂ = 8 g
Pressure (P) = 4 atm
Temperature (T) = 27°C = 300 K
Gas Constant (R) = 0.082 L atm mol⁻¹ K⁻¹
Volume (V) = ?
Molar mass of H₂ = 2 g/mol
Number of moles (n) = \frac{\text{Mass}}{\text{Molar Mass}}
= \frac{8}{2}
= 4 mol
Ideal Gas Equation : PV=nRT
Volume (V) = \frac{\text{nRT}}{\text{P}}
= \frac{4 × 0.082 × 300}{4}
= 24.6 L
Hence, the volume of 8 g of H₂ gas is 24.6 L
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