QQuestion
If x\over2 = y\over3 = z\over4 then find the value of (3x + 4y + 8z) / (x + 3y).
✓Answer
Let the common ratio be k. Then,
x = 2k, y = 3k, and z = 4k.
Substitute these into the expression:
\text{3x + 4y + 8z} \over \text{x + 3y} = \text{3(2k) + 4(3k) + 8(4k)} \over \text{(2k) + 3(3k)}
= \text{6k + 12k + 32k} \over \text{2k + 9k}
= \text{50k} \over \text{11k}
= \frac{50}{11} .
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