QQuestion
In the given figure ‘O’ is the centre of the circle. PQ is a tangent to the circle at B and AB = AC. If ∠CBQ = 40°, find the unknown angles x, y, z and w.

In the given figure ‘O’ is the centre of the circle. PQ is a tangent to the circle at B and AB = AC. If ∠CBQ = 40°, find the unknown angles x, y, z and w.

Given, ∠CBQ = 40°
In a circle, the angle between a tangent and a chord through the point of contact is equal to the angle in the opposite (alternate) segment of the circle.
∠BAC = ∠CBQ = 40°
x = 40°
Since, AB = AC.
∠ABC = ∠BCA [Angles opposite to equal sides of a triangle are equal]
In triangle ABC,
∠ABC + ∠BAC + ∠BCA = 180°
2∠ABC + 40° = 180°
2∠ABC = 180° – 40°
2∠ABC = 140°
∠ABC = 70°.
We know that,
The angle which an arc subtends at the center is double that which it subtends at any point on the remaining part of the circumference.
∠BOC = 2∠BAC
y = 2x
y = 80°.
In triangle OBC,
OB = OC (Radii of same circle)
∠OBC = ∠OCB (Angles opposite to equal sides in a triangle are equal)
By angle sum property of triangle,
∠OBC + ∠OCB + ∠BOC = 180°
2∠OBC + 80° = 180°
2∠OBC = 100°
∠OBC = 50°
From figure,
w = ∠ABC – ∠OBC = 70° – 50° = 20°.
We know that,
Sum of opposite angles of a cyclic quadrilateral is 180°.
In cyclic quadrilateral ABCD,
∠ABC + ∠ADC = 180°
70° + z = 180°
z = 180° – 70° = 110°.
Hence, x = 40°, y = 80°, z = 110°, w = 20°.
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