Volume of 22 g of CO₂ at S.T.P. is [C = 12, O = 16]:
(a) 22.4 litre
(b) 11.2 litre
(c) 2.24 litre
(d) 1.12 litre
WBBSE
Class X
Physical Science
Chemical Calculations
01 Mark
2025
(b) 11.2 litre
Explanation
Molar mass of CO₂ = 12 + (16 × 2) = 44 g/mol
Number of moles = \text{Mass} \over \text{Molar mass} = 22 \over 44 = 0.5 mol
Volume = Number of moles × 22.4 L
= 0.5 × 22.4
= 11.2 L
Therefore, the volume of 22 g of CO₂ at S.T.P. is 11.2 litres.
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