How much H2 is obtained when steam is passed over 21 g red hot iron? What would be the volume of that H2 at STP? [Fe=56] [2+1]
OR
SO3 is prepared by oxidising SO2 in presence of O2. How much SO2 in grams will be required to produce 40 g of SO3? (S = 32, O = 16)
Balanced Eq: 3Fe + 4H2O → Fe3O4 + 4H2
. 3 × 56 g = 168 g 4 × 2 = 8 g
Amount of H2 produced by 168 g of Fe = 8 g
or, Amount of H2 produced by 21 g of Fe = 8\over168 × 21 g = 1 g
Volume of 2 g of H2 = 22.4 liters
∴ Volume of 1 g of H2 = 22.4 / 2 = 11.2 liters
OR
Balanced Eq: 2SO2 + O2 → 2SO3
. 64 g 32 g 80 g
To produce 80 g of SO3, 64 g of SO2 is required.
∴ To produce 40 g of SO3, 32 g of SO2 is required.
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