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Question

Two pillars of equal heights are at the point A and B on the opposite side of the road which is 120 m wide. From a point C on the line joining the foots of the pillars, the angle of elevation of the top of the pillar at A and B are 60° and 30° respectively. Find AC.

WBBSE Class X Mathematics Application of Trigonometric Ratios 05 Mark 2024

Answer

Two pillars of equal heights are at the point A and B on the opposite side of the road which is 120 m wideLet the common height of the two pillars be h.

Let AC = x. Then CB = 120−x.

In Δ ACD

tan 30° = h\over x

⇒ h = x tan 30° = x\over √3

In Δ BCE

tan 60° = h\over 120 - x

⇒ √3 = {x\over √3}\over 120 - x

⇒ √3 = x\over √3(120 - x)

⇒ √3 × √3(120 – x) = x

⇒ 3 (120 – x) = x

⇒ 360 – 3x = x

⇒ 360 = 4x

⇒ x = 360\over 4 = 90 m

∴ AC = 90 m

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