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ICSE Class 10 Chemistry (Science Paper – 2) Solved Paper 2023

Complete ICSE Class X Chemistry 2023 question paper with accurate, step-by-step solutions.

ICSEClass XChemistry202380 Marks2 h44 Questions

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Section A (40 Marks)

(Attempt all questions from this section)

Question 1 (i)

1 (i)Periodic Table, Periodic Properties and Variations of PropertiesEasy1 Mark

An element in period 3, whose electron affinity is zero:

Answer

(d) Argon

Explanation:

Argon belongs to period 3. It is an inert element and its octet is complete hence, it’s electron affinity is zero.

Question 1 (ii)

1 (ii)Periodic Table, Periodic Properties and Variations of PropertiesEasy1 Mark

An element with the largest atomic radius among the following is:

(a) Carbon

(b) Nitrogen

(c) Lithium

(d) Beryllium

Answer

c. Lithium

Explanation:

The given elements belong to the second period and Lithium is the first element of second period. Atomic size decreases from left to right in a period hence, Lithium will have the largest atomic radius.

Question 1 (iii)

1 (iii)MetallurgyEasy1 Mark

The compound that is not an ore of aluminium:

Answer

(c) Fluorspar

Explanation:

Fluorspar is calcium fluoride [CaF2], not an ore of aluminium.

The other three options are ores of aluminium:

  • Bauxite — Al2O3·2H2O
  • Corundum — Al2O3
  • Cryolite — Na3AlF6

Question 1 (iv)

1 (iv)Mole Concept and StoichiometryEasy1 Mark

The vapour density of CH₃OH is …………… (At. Wt. C=12, H=1, O=16)

Answer

c. 16

Explanation:

Molecular mass of methyl alcohol [CH3OH] = 12 + 3(1) + 16 + 1 = 32

Vapour density = molecular mass ÷ 2

= 32 ÷ 2

= 16

Question 1 (v)

1 (v)ElectrolysisEasy1 Mark

Which of the following reactions takes place at the anode during the electroplating of an article with silver?

Answer

(a) Ag − 1e− ⟶ Ag1+

Explanation:

  • During electroplating, the silver anode loses electrons.
  • Silver atoms form Ag1+ ions in the solution.

Anode reaction – Ag − 1e− ⟶ Ag1+

Question 1 (vi)

1 (vi)Analytical ChemistryEasy1 Mark

The metallic hydroxide which forms a deep inky blue solution with excess ammonium hydroxide solution is:

Answer

(b) Cu(OH)2

Explanation:

Cu(OH)2 reacts with a solution of excess ammonium hydroxide to form a deep blue solution of tetrammine copper [II] sulphate.

Cu(OH)2 + (NH4)2SO4 + 2NH4OH ⟶ [Cu(NH3)4]SO4 + 4H2O

Question 1 (vii)

1 (vii)Organic ChemistryEasy1 Mark

An example of a cyclic organic compound is:

Answer

(d) Benzene

Explanation:

In benzene, six carbon atoms form a ring structure and there are three single and three double bonds between the carbon atoms. Hence, benzene is a cyclic compound.

Question 1 (viii)

1 (viii)Hydrogen ChlorideEasy1 Mark

In the laboratory preparation, HCl gas is dried by passing through:

Answer

(b) Concentrated sulphuric acid

Explanation:

Concentrated Sulphuric acid only removes the moisture content of HCl gas but does not react with it. Hence, it is used as a drying agent for HCl gas.

Question 1 (ix)

1 (ix)Nitric AcidEasy1 Mark

The nitrate which on thermal decomposition leaves behind a residue which is yellow when hot and white when cold:

Answer

(d) Zinc nitrate

Explanation:

On heating, zinc nitrate decomposes to form zinc oxide, nitrogen dioxide, and oxygen.

2\mathrm{Zn(NO_3)_2} \xrightarrow{\Delta} 2\mathrm{ZnO} + 4\mathrm{NO_2} + \mathrm{O_2}

The solid residue is zinc oxide (ZnO), which is yellow when hot and white when cold.

Question 1 (x)

1 (x)Nitric AcidEasy1 Mark

The salt formed when concentrated sulphuric acid reacts with KNO3 above 200°C:

Answer

(a) K2SO4

Explanation:

Above 200°C, potassium nitrate reacts with concentrated sulphuric acid to form potassium sulphate and nitric acid.

The balanced equation is:

2\mathrm{KNO_3} + \mathrm{H_2SO_4} \xrightarrow{>200^\circ\mathrm{C}} \mathrm{K_2SO_4} + 2\mathrm{HNO_3}

Therefore, the salt formed is potassium sulphate (K2SO4).

Question 1 (xi)

1 (xi)Hydrogen ChlorideEasy1 Mark

The property exhibited by concentrated sulphuric acid when it is used to prepare hydrogen chloride gas from potassium chloride: [1]

Answer

(d) Non-volatile acid property

Explanation:

Concentrated sulphuric acid has a high boiling point and is non-volatile. It displaces the more volatile hydrogen chloride from potassium chloride.

Question 1 (xii)

1 (xii)Organic ChemistryEasy1 Mark

The hydrocarbon formed when sodium propanoate and soda lime are heated together:

Answer

b. Ethane

Explanation:

Heating sodium propanoate with soda lime causes decarboxylation. The alkane formed has one carbon atom fewer than the original carboxylate.

\mathrm{CH_3CH_2COONa}+\mathrm{NaOH}\xrightarrow{\mathrm{CaO},\,\Delta}\mathrm{C_2H_6}+\mathrm{Na_2CO_3}

Sodium propanoate has three carbon atoms; the hydrocarbon product, ethane, has two.

Question 1 (xiii)

1 (xiii)Acids, Bases and SaltsEasy1 Mark

The acid which does not form acid salt by a basic radical:

Answer

(d) CH3COOH

Explanation:

Acetic acid is monobasic: only the hydrogen of its carboxyl (–COOH) group is replaceable by a basic radical.

Replacing this hydrogen forms a normal salt, such as sodium acetate (CH3COONa). No replaceable acidic hydrogen remains to form an acid salt.

Question 1 (xiv)

1 (xiv)Organic ChemistryEasy1 Mark

The general formula of hydrocarbons with single covalent bonds is:

Answer

(a) CnH2n+2

Explanation:

The open-chain saturated hydrocarbons are called alkanes. They contain only single covalent bonds and have the general formula CnH2n+2, where n is the number of carbon atoms.

Question 1 (xv)

1 (xv)Acids, Bases and SaltsEasy1 Mark

The indicator which changes to pink colour in an alkaline solution is:

Answer

(d) Phenolphthalein

Explanation:

Phenolphthalein is colourless in acidic and neutral solutions. It turns pink in an alkaline solution.

Question 2 (i)

2 (i)Chemical BondingModerate5 Marks

Match the Column A with Column B: 

Column A Column B
(a) Sodium chloride 1. has two shared pair of electrons
(b) Methane 2. has high melting and boiling points
(c) Hydrogen chloride gas 3. a greenhouse gas
(d) Oxidation reaction 4. has low melting and boiling points
(e) Water 5. Zn − 2e− ⟶ Zn2+
6. S + 2e− ⟶ S2−
Answer

(a)–2: Sodium chloride — has high melting and boiling points.

(b)–3: Methane — a greenhouse gas.

(c)–4: Hydrogen chloride gas — has low melting and boiling points.

(d)–5: Oxidation reaction — Zn − 2e− → Zn2+.

(e)–1: Water — has two shared pairs of electrons.

Question 2 (ii)

2 (ii)MetallurgyModerate5 Marks

The following sketch illustrates the process of conversion of Alumina to Aluminium: [5]

Electrolytic cell showing the electrolyte mixture and labels X, Y and Z.

Study the diagram and answer the following:

(a) Name the constituent of the electrolyte mixture which has a divalent metal in it.

(b) Name the powdered substance ‘X’ sprinkled on the surface of the electrolyte mixture.

(c) What is the name of the process?

(d) Write the reactions taking place at the electrodes ‘Y’ (anode) and ‘Z’ (cathode) respectively.

Answer

(a) Fluorspar, CaF2.

(b) Powdered coke.

(c) Hall–Héroult process.

(d) At Y (anode):

2O2− → O2 + 4e−

At Z (cathode):

Al3+ + 3e− → Al

Question 2 (iii)

2 (iii)Periodic Table, Periodic Properties and Variations of PropertiesModerate1 Mark

Fill in the blanks with the choices given in the brackets:

(a) Metals are good …………… [oxidizing agents /reducing agents]

(b) Non-polar covalent compounds are …………… [good / bad] conductors of heat and electricity.

(c) Higher the pH value of a solution, the more is …………… [acidic / alkaline] it is.

(d) …………… [Silver chloride / Lead chloride] is a white precipitate that is soluble in excess of Ammonium hydroxide solution.

(e) Conversion of ethene to ethane is an example of …………… . [hydration / hydrogenation]

Answer

(a) Metals are good reducing agents

(b) Non-polar covalent compounds are bad conductors of heat and electricity.

(c) Higher the pH value of a solution, the more alkaline it is.

(d) Silver chloride is a white precipitate that is soluble in excess of Ammonium hydroxide solution.

(e) Conversion of ethene to ethane is an example of hydrogenation.

Question 2 (iv)

2 (iv)Acids, Bases and SaltsModerate5 Marks

State the terms/process for the following:

(a) The energy released when an atom in the gaseous state accepts an electron to form an anion.

(b) Tendency of an element to form chains of identical atoms.

(c) The name of the process by which Ammonia is manufactured on a large scale.

(d) A type of salt formed by partial replacement of hydroxyl radicals with an acid radical.

(e) The ratio of the mass of a certain volume of gas to the same volume of hydrogen measured under the same conditions of temperature and pressure.

Answer

(a) Electron affinity

(b) Catenation

(c) Haber’s process

(d) Basic salt

(e) Vapour density

Question 2 (v)

2 (v)Organic ChemistryModerate5 Marks

Give the structural formulas and IUPAC names as directed: 

(a) Give the structural formula of the following organic compounds:

  1. 2-chlorobutane
  2. Methanal
  3. But-2-yne

(b) Give the IUPAC name of the following organic compounds:

Organic structures numbered 1 and 2 for IUPAC naming.

Answer

(a) Structural formulas:

1. 2-chlorobutane

Displayed structural formula of 2-chlorobutane, with chlorine bonded to carbon 2.

2. Methanal

Displayed structural formula of methanal: carbon double-bonded to oxygen and single-bonded to two hydrogen atoms.

3. But-2-yne

Displayed structural formula of but-2-yne with a triple bond between carbon 2 and carbon 3.

(b) IUPAC names:

  1. Ethanoic acid
  2. Butan-2-ol
S

Section B (40 Marks)

(Attempt any four questions)

Question 3 (i)

3 (i)Analytical ChemistryModerate2 Marks

Identify the cation in each of the following cases: 

(a) Ammonium hydroxide solution when added to Solution B gives a white precipitate which does not dissolve in excess of ammonium hydroxide solution.

(b) Sodium hydroxide solution when added to Solution C gives a white precipitate which is insoluble in excess of sodium hydroxide solution.

Answer

(a) Lead(II) ion, Pb2+.

(b) Calcium ion, Ca2+.

Question 3 (ii)

3 (ii)ElectrolysisModerate2 Marks

Fill in the blanks by choosing the correct answer from the brackets:

(a) During electrolysis, the compound …………… in its molten state liberates reddish brown fumes at the anode. [NaCl/PbBr2]

(b) The ion which could be discharged most readily during electrolysis is …………… [Fe2+/Cu2+]

Answer

(a) PbBr2 (lead bromide).

(b) Cu2+

Question 3 (iii)

3 (iii)MetallurgyModerate3 Marks

Arrange the following as per the instruction given in the brackets:

(a) Al, K, Mg, Ca (decreasing order of its reactivity)

(b) N, Be, O, C (increasing order of non-metallic character)

(c) P, Si, F, Be (decreasing order of valence electrons)

Answer

(a) K > Ca > Mg > Al

(b) Be < C < N < O

(c) F > P > Si > Be

Question 3 (iv)

3 (iv)AmmoniaModerate3 Marks

Complete and balance the following equations:

(a) NH4Cl + Ca(OH)2 →

(b) CuSO4 + NH4OH →

(c) Cu + Conc. HNO3 →

Answer

(a) 2NH4Cl + Ca(OH)2 → CaCl2 + 2NH3 + 2H2O

(b) CuSO4 + 2NH4OH → (NH4)2SO4 + Cu(OH)2↓

(c) Cu + 4HNO3 (conc.) → Cu(NO3)2 + 2NO2 + 2H2O

Question 4 (i)

4 (i)AmmoniaModerate2 Marks

State a relevant reason for the following: [2]

(a) Hydrogen chloride gas cannot be dried over quick lime.

(b) Ammonia gas is not collected over water.

Answer

(a) Quicklime (CaO) reacts with hydrogen chloride, forming calcium chloride and water. It would absorb the gas itself, so it cannot be used to dry HCl.

CaO + 2HCl → CaCl2 + H2O

(b) Ammonia is highly soluble in water and would dissolve instead of being collected.

Question 4 (ii)

4 (ii)MetallurgyModerate2 Marks

Identify the alloy in each case from the given composition:

(a) Aluminium, magnesium, manganese, copper

(b) Iron, nickel, chromium, carbon

Answer

(a) Duralumin

(b) Stainless steel

Question 4 (iii)

4 (iii)Mole Concept and StoichiometryModerate3 Marks

Ethane burns in oxygen according to the chemical equation:

2C2H6 + 7O2 → 4CO2 + 6H2O

If 80 ml of ethane is burnt in 300 ml of oxygen, find the composition of the resultant gaseous mixture when measured at room temperature.

Answer

[By Lussac’s law]

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

2 vol. : 7 vol. → 4 vol.

(i) To calculate the volume of CO₂ formed:

C₂H₆ : CO₂

2 vol. : 4 vol.

80 ml : x

∴ x = (4/2) × 80 = 160 ml

Hence, volume of carbon dioxide formed = 160 ml

(ii) To calculate the volume of unused O₂:

C₂H₆ : O₂

2 vol. : 7 vol.

80 ml : x

∴ x = (7/2) × 80 = 280 ml

Unused oxygen = 300 − 280 = 20 ml

Hence, volume of unused oxygen = 20 ml

Therefore, the resultant gaseous mixture consists of 160 ml of carbon dioxide and 20 ml of unused oxygen.

Question 4 (iv)

4 (iv)AmmoniaModerate3 Marks

The following questions are pertaining to the laboratory preparation of Ammonia gas from Magnesium nitride:

(a) Write a balanced chemical equation for its preparation.

(b) Why is this method seldom used?

(c) How do you identify the gas formed?

Answer

(a) Mg3N2 + 6H2O → 3Mg(OH)2 + 2NH3

(b) Magnesium nitride is expensive, so this method is seldom used.

(c) Ammonia turns moist red litmus paper blue. It also forms dense white fumes of ammonium chloride when a glass rod dipped in concentrated hydrochloric acid is brought near the gas.

NH3 + HCl → NH4Cl

Question 5 (i)

5 (i)MetallurgyModerate2 Marks

Write one use of the following alloys:

(a) Bronze

(b) Fuse metal

Answer

(a) Bronze is used for making statues.

(b) Fuse metal is used for making electrical fuse wires.

Question 5 (ii)

5 (ii)Chemical BondingEasy2 Marks

Draw the electron dot structure for the following:

(a) Ammonium ion

(b) A molecule of nitrogen

[At. No.: N=7, H=1]

Answer

(a) Ammonium ion:

Ammonium Ion

(b) Nitrogen molecule:

Nitrogen Dot Structure

Question 5 (iii)

5 (iii)Organic ChemistryEasy3 Marks

Give a balanced chemical equation for the following conversions with conditions:

(a) Ethene from ethanol

(b) Ethyne from calcium carbide

(c) Monochloromethane from methane

Answer

(a) Ethene from ethanol:

\mathrm{C_2H_5OH \xrightarrow[\text{excess}]{170^\circ\mathrm{C},\ conc.\ H_2SO_4} C_2H_4 + H_2O}

(b) Ethyne from calcium carbide:

CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂

(c) Monochloromethane from methane:

\mathrm{CH_4 + Cl_2 \xrightarrow{\Delta,\ diffused\ sunlight} CH_3Cl + HCl}

Question 5 (iv)

5 (iv)Analytical ChemistryEasy3 Marks

Study the following observations and name the anions present in each of the reactions.

(a) When a crystalline solid ‘P’ is warmed with concentrated H2SO4 and copper turnings a reddish brown gas is released.

(b) When few drops of dilute sulphuric acid is added to Salt ‘R’ and heated, a colourless gas is released which turns moist lead acetate paper silvery black.

(c) When few drops of barium nitrate solution is added to the salt solution ‘Q’, a white precipitate is formed which is insoluble in HCl.

Answer

(a) Nitrate ion, NO₃⁻.

(b) Sulphide ion, S²⁻.

(c) Sulphate ion, SO₄²⁻.

Question 6 (i)

6 (i)Chemical BondingModerate2 Marks

Define / State:

(a) Electronegativity.

(b) Gay-Lussac’s law of combining volumes.

Answer

(a) Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons towards itself.

(b) When gases react, they do so in volumes that bear a simple whole-number ratio to one another and to the volume of gaseous products, provided all volumes are measured at the same temperature and pressure.

Question 6 (ii)

6 (ii)Mole Concept and StoichiometryEasy2 Marks

The Empirical formula of an organic compound is CHCl2.

If its relative molecular mass is 168, what is its molecular formula?

[At. Wt. C = 12, H = 1, Cl = 35.5]

Answer

Empirical formula mass = 12 + 1 + 2(35.5) = 84.

n = 168 ÷ 84 = 2.

Therefore, molecular formula = (CHCl₂)₂ = C₂H₂Cl₄.

Question 6 (iii)

6 (iii)Practical ChemistryEasy3 Marks

Choose the substances given in the box below to answer the following questions:

Iron Magnesium sulphite Zinc Sodium sulphide
Lead Ferric chloride Copper Ferrous sulphate

(a) The metal that will not produce hydrogen gas when reacted with dilute acids.

(b) The compound that will produce sulphur dioxide gas when reacted with dilute HCl.

(c) The solution of this compound produces dirty green precipitate with NaOH.

Answer

(a) Copper

(b) Magnesium Sulphite

(c) Ferrous Sulphate

Question 6 (iv)

6 (iv)AmmoniaModerate3 Marks

State one relevant observation for each of the following:

(a) To the copper nitrate solution, initially few drops of sodium hydroxide solution is added and then added in excess.

(b) Burning of ammonia in excess of oxygen.

(c) Dry ammonia gas is passed over heated PbO.

Answer

(a) A light-blue precipitate of copper(II) hydroxide is formed. It remains insoluble in excess sodium hydroxide solution.

(b) Ammonia burns with a greenish-yellow flame, forming nitrogen and water vapour.

(c) The buff-yellow lead(II) oxide is reduced to grey metallic lead.

Question 7 (i)

7 (i)Organic ChemistryModerate2 Marks

Name the following:

(a) Organic compounds with same molecular formula but different structural formula.

(b) Group of organic compounds where the successive members follow a regular structural pattern, successive compounds differ by a ‘CH2’ group.

Answer

(a) Isomers.

(b) Homologous series.

Question 7 (ii)

7 (ii)Chemical BondingModerate2 Marks

Give a reason for each:

(a) Ionisation potential decreases down a group.

(b) Ionic compounds do not conduct electricity in the solid state.

Answer

(a) Down a group, atomic size and shielding increase; therefore the outer electron is held less strongly and is removed more easily.

(b) In a solid ionic compound, the ions are fixed in the crystal lattice and cannot move to carry electric current.

Question 7 (iii)

7 (iii)Mole Concept and StoichiometryModerate3 Marks

Calculate:

(a) The percentage of phosphorus in the fertilizer super phosphate Ca(H2PO4)2 correct to 1 decimal point.

(b) Write the empirical formula of C8H18

[At. Wt. H=1, P=31, O=16, Ca=40]

Answer

(a) Formula mass of Ca(H₂PO₄)₂ = 40 + 2[2(1) + 31 + 4(16)] = 234.

Mass of phosphorus = 2 × 31 = 62.

\frac{62}{234}\times100=26.5\%

(b) C₈H₁₈ = (C₄H₉)₂.

Empirical formula = C₄H₉.

Question 7 (iv)

7 (iv)ElectrolysisModerate3 Marks

Answer the following with reference to the electrolytic refining of copper:

(a) What is used as the anode?

(b) Where is pure copper deposited?

(c) Write the cathode reaction.

Answer

(a) A block of impure copper is used as the anode.

(b) Pure copper is deposited on the cathode, which is a thin sheet of pure copper.

(c) Cu²⁺ + 2e⁻ → Cu

Question 8 (i)

8 (i)ElectrolysisModerate2 Marks

Arrange the following according to the instructions given in brackets:

(a) C2H2, C3H6, CH4, C2H4 (In the increasing order of the molecular weight)

(b) Cu2+, Na+, Zn2+, Ag+ (The order of Preferential discharge at the cathode)

Answer

(a) Molecular weight of C2H2 = 2[12] + 2[1] = 26

Molecular weight of C3H6 = 3[12] + 6[1] = 42

Molecular weight of CH4 = 12 + 4[1] = 16

Molecular weight of C2H4 = 2[12] + 4[1] = 28

Hence, increasing order of molecular weights is :

CH4 < C2H2 < C2H4 < C3H6

(b) Ag+, Cu2+, Zn2+, Na+

Question 8 (ii)

8 (ii)Acids, Bases and SaltsModerate2 Marks

Differentiate between the following pairs based on the criteria given in the brackets:

(a) Cane sugar and hydrated copper sulphate [using concentrated H2SO4]

(b) Sulphuric acid and hydrochloric acid [type of salts formed]

Answer

(a) Cane sugar is dehydrated by concentrated sulphuric acid and turns black due to carbon formation:

\mathrm{C_{12}H_{22}O_{11}\xrightarrow{\text{conc. }H_2SO_4}12C+11H_2O}

Hydrated copper(II) sulphate changes from blue to white anhydrous copper(II) sulphate.

(b) Sulphuric acid forms sulphate salts, whereas hydrochloric acid forms chloride salts.

Question 8 (iii)

8 (iii)Acids, Bases and SaltsModerate3 Marks

Convert the following reactions into a balanced chemical equation:

(a) Ammonia to nitric oxide using oxygen and platinum catalyst.

(b) Sodium hydroxide to sodium sulphate using sulphuric acid.

(c) Ferrous sulphide to hydrogen sulphide using hydrochloric acid.

Answer

(a) \mathrm{4NH_3+5O_2\xrightarrow[\ 800^\circ C\ ]{Pt}4NO+6H_2O}

(b) 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

(c) FeS + 2HCl → FeCl₂ + H₂S↑

Question 8 (iv)

8 (iv)Chemical BondingModerate3 Marks

Choose the answer from the list which fits in the description:

[CCl4, PbO, NaCl, CuO, NH4Cl]

(a) A compound which undergoes thermal dissociation.

(b) An amphoteric oxide.

(c) A compound which is a non-electrolyte.

Answer

(a) NH₄Cl

(b) PbO

(c) CCl₄