Madhyamik Class 10 Physical Science Solved Paper 2026

Madhyamik Class 10 Physical Science Question Paper Solved 2026

Physical Science

Time – Three Hours Fifteen Minutes

(First fifteen minutes for reading the Question paper only)

Full Marks – 90

(For Regular and Sightless Regular Candidates)

Full Marks – 100

(For External and sightless External Candidates)


Special credits will be given for answers which are brief and to the point.

Marks will be deducted for spelling mistakes, untidiness and bad handwriting.


Figures in the margin indicate full marks for each Question.

Only the External Candidates will answer Group -E

Figures in the margin indicate full marks for each Question.

Question 1 | Group A
Multiple choice Questions. Four alternative answers are given for each of the following Questions. Write the correct one. [1 × 15 = 15]
1.1

Which of the following gases does not help in the depletion of the ozone layer?

(a) CFC

(b) NO

(c) CO₂

(d) NO₂

EasyConcerns about our Environment01 Mark marks
Answer

(c) CO₂

Explanation

Carbon dioxide (CO₂) is a greenhouse gas that contributes to global warming, but it does not directly take part in the depletion of the ozone layer.

1.2

The mass of 11.2 L of NH₃ gas at S.T.P. is:

[N = 14, H = 1]

(a) 17 g

(b) 8.5 g

(c) 34 g

(d) 11.2 g

ModerateBehaviour of Gases01 Mark marks
Answer

(b) 8.5 g

Explanation

At S.T.P., 1 mole of any gas occupies 22.4 L.

Therefore, 11.2 L of NH₃ = \frac{11.2}{22.4} = 0.5 mol

Molar mass of NH₃ = 14 + (1 × 3) = 17 g/mol

Mass of 0.5 mol NH₃ = 0.5 × 17 = 8.5 g

1.3

According to the following chemical equation, what volume of oxygen at S.T.P. is required for the complete combustion of 5 moles of methane?

CH₄ + 2O₂ → CO₂ + 2H₂O

(a) 224 L

(b) 448 L

(c) 44.8 L

(d) 22.4 L

ModerateChemical Calculations01 Mark marks
Answer

(a) 224 L

Explanation

CH₄ + 2O₂ → CO₂ + 2H₂O

From the balanced chemical equation,

1 mole of CH₄ requires 2 moles of O₂.

Therefore, 5 moles of CH₄ require = 5 × 2

= 10 moles of O₂

At S.T.P., 1 mole of any gas occupies 22.4 L.

Volume of 10 moles of O₂ = 10 × 22.4 = 224 L

1.4

The SI unit of thermal conductivity is:

(a) W m⁻¹ K⁻¹

(b) cal m⁻¹ °C⁻¹

(c) W m K⁻¹

(d) W m² K⁻¹

EasyThermal phenomena01 Mark marks
Answer

(a) W m⁻¹ K⁻¹

Explanation

The SI unit of thermal conductivity is watt per metre per kelvin (W m⁻¹ K⁻¹).

Thermal conductivity is defined as the amount of heat conducted per second through unit area of a material of unit thickness when the temperature difference between its two faces is 1 K.

1.5

The least distance of distinct vision for a normal human eye is:

(a) 25 cm

(b) 100 cm

(c) Infinity

(d) 0 cm

EasyLight – Reflection and Refraction01 Mark marks
Answer

(a) 25 cm

Explanation

The least distance of distinct vision (near point) for a normal human eye is 25 cm.

It is the minimum distance from the eye at which an object can be seen clearly and distinctly without strain.

1.6

When a ray of light is incident normally on the surface of a glass slab, the angle of refraction will be:

(a) 0°

(b) 90°

(c) 180°

(d) 30°

EasyLight – Reflection and Refraction01 Mark marks
Answer

(a) 0°

Explanation

When a ray of light is incident normally on the surface of a glass slab, the angle of incidence is 0°.

According to Snell’s law, the ray passes undeviated along the normal. Therefore, the angle of refraction is also 0°.

1.7

The total charge of how many electrons is equal to 1 coulomb?

(a) 1.6 × 10¹⁹

(b) 6.25 × 10¹⁰

(c) 6.25 × 10¹⁸

(d) 6.023 × 10²³

EasyCurrent Electricity01 Mark marks
Answer

(c) 6.25 × 10¹⁸

Explanation

Charge of one electron = 1.6 × 10⁻¹⁹ C

Number of electrons corresponding to 1 C = \frac{1}{1.6 \times 10^{-19}}

= 6.25 × 10¹⁸

1.8

With increase in temperature, the resistance decreases in:

(a) Copper

(b) Nichrome

(c) Glass

(d) Silicon

EasyCurrent Electricity01 Mark marks
Answer

(d) Silicon

Explanation

Silicon is a semiconductor. As its temperature increases, the number of free charge carriers also increases, causing its electrical resistance to decrease.

1.9

If the mass of an electron is m, then the mass of a β-particle is:

(a) m

(b) 2m

(c) 3m

(d) 4m

EasyAtomic Nucleus01 Mark marks
Answer

(a) m

Explanation

A β-particle (β⁻) is a high-speed electron emitted from the nucleus during beta decay.

Therefore, the mass of a β-particle is equal to the mass of an electron.

1.10

If the atomic number of an element is 19, in which group of the modern periodic table is the element placed?

(a) Group 1

(b) Group 2

(c) Group 18

(d) Group 9

EasyPeriodic Table01 Mark marks
Answer

(a) Group 1

Explanation

An element with atomic number 19 is Potassium (K).

Electronic configuration of potassium: 2, 8, 8, 1

Since it has one electron in its outermost shell, it belongs to Group 1 (Alkali Metals) of the modern periodic table.

1.11

The substance used for drying ammonia gas is:

(a) CaCl₂

(b) CaO

(c) H₂SO₄

(d) P₂O₅

EasyInorganic Chemistry01 Mark marks
Answer

(b) CaO

Explanation

Quick lime (CaO) is used for drying ammonia gas (NH₃) because it absorbs moisture without reacting with ammonia.

Concentrated H₂SO₄ and P₂O₅ cannot be used because they react with ammonia.
Anhydrous CaCl₂ is also not suitable because it forms an addition compound with ammonia.

1.12

Which of the following elements is not present in Duralumin?

(a) Al

(b) Zn

(c) Cu

(d) Mg

EasyMetallurgy01 Mark marks
Answer

(b) Zn

Explanation

Duralumin is an alloy composed mainly of:

  • Aluminium (Al)
  • Copper (Cu)
  • Magnesium (Mg)
  • Manganese (Mn)

Zinc (Zn) is not a constituent of duralumin.

1.13

What will be the colour of the solution formed when excess aqueous ammonia is added to aqueous copper sulphate solution?

(a) Yellow

(b) Orange

(c) Green

(d) Deep blue

EasyInorganic Chemistry01 Mark marks
Answer

(d) Deep blue

Explanation

When excess aqueous ammonia (NH₄OH) is added to copper sulphate (CuSO₄) solution, a deep blue solution is formed due to the formation of the tetraammine copper(II) complex.

1.14

Which of the following has the highest electrical conductivity?

(a) Aqueous solution of sugar

(b) Pure water

(c) Liquid hydrogen chloride

(d) None of these

EasyElectrolysis01 Mark marks
Answer

(d) None of these

Explanation

  • Aqueous sugar solution: Sugar is a covalent compound that dissolves as neutral molecules, not ions.
  • Pure water: Contains almost no free ions (extremely weak self-ionization).
  • Liquid HCl: Pure covalent liquid without free ions (it only ionizes and conducts when dissolved in water).
1.15

The value of the H-C-H bond angle in a methane molecule is –

(a) 109°28′

(b) 108°29′

(c) 100°

(d) 180°

EasyOrganic Chemistry01 Mark marks
Answer

(a) 109°28′

Explanation:

Methane (CH4) has a tetrahedral structure with four identical single bonds around the central carbon atom. In a regular tetrahedron, the bond angle between any two bonds is 109°28′ (or about 109.5°).

Question 2 | Group B
Answer the following Questions (alternatives are to be noted): [1 × 21 = 21]
2.1

Write the name of the main component of biogas.

EasyConcerns about our Environment01 Mark marks
Answer

Methane (CH₄)

Explanation

Biogas mainly contains methane, along with smaller amounts of gases such as carbon dioxide.

Write the name of a gas involved in our breathing process whose increase in the atmosphere causes global warming.

EasyConcerns about our Environment01 Mark marks
Answer

Carbon dioxide (CO₂)

Explanation

Carbon dioxide is involved in the breathing/respiration cycle and is also a greenhouse gas. An increase in its concentration in the atmosphere contributes to global warming.

2.2

What is meant by saying the calorific value of natural gas is 50 kJ/g?

EasyConcerns about our Environment01 Mark marks
Answer

The calorific value of natural gas is 50 kJ/g means that 50 kJ of heat energy is produced when 1 g of natural gas is completely burnt in oxygen.

2.3

State whether the following statement is true or false: Equal volumes of all gases under the same conditions of temperature and pressure contain an equal number of atoms.

EasyBehaviour of Gases01 Mark marks
Answer

False

Explanation

According to Avogadro’s Law, equal volumes of all gases at the same temperature and pressure contain an equal number of molecules, not necessarily an equal number of atoms.

2.4

Write the SI unit of the ideal gas constant.

EasyBehaviour of Gases01 Mark marks
Answer

The SI unit of the ideal gas constant R is: J mol⁻¹ K⁻¹

2.5

State whether the following statement is true or false: The real expansion of a liquid depends on the expansion of the vessel in which the liquid is kept.

EasyThermal phenomena01 Mark marks
Answer

False

Explanation

The real expansion of a liquid is independent of the expansion of the vessel. It is the actual increase in the volume of the liquid due to heating.

If the length and cross-sectional area of a conductor remain unchanged, what is the relationship between the thermal resistance and thermal conductivity of that conductor?

EasyThermal phenomena01 Mark marks
Answer

Thermal resistance, Rt = \frac{\text{L}}{\text{K}\text{A}}

Since the length L and cross-sectional area A remain constant,

Rt \frac{1}{\text{K}}

Therefore, thermal resistance is inversely proportional to thermal conductivity.

2.6

Which color of light undergoes the minimum scattering?

EasyLight – Reflection and Refraction01 Mark marks
Answer

Red light

Explanation

Red light has the longest wavelength among the colours of visible light. According to Rayleigh’s law, the intensity of scattering is inversely proportional to the fourth power of wavelength:

Scattering ∝ \frac{1}{\text{λ}^4}

Therefore, red light undergoes the minimum scattering.

2.7

Give an example of a natural spectrum.

EasyLight – Reflection and Refraction01 Mark marks
Answer

Rainbow

Explanation

A rainbow is an example of a natural spectrum. It is formed due to the dispersion of sunlight by tiny water droplets present in the atmosphere.

2.8

Write the name of a device where electrical energy is converted into mechanical energy.

EasyCurrent Electricity01 Mark marks
Answer

Electric motor

2.9

How much work has to be done to move an electric charge against a potential difference?

EasyCurrent Electricity01 Mark marks
Answer

The work required to move a charge Q through a potential difference V is QV joule.

2.10

Write the name of the positively charged radioactive particle.

EasyAtomic Nucleus01 Mark marks
Answer

Alpha (α) particle.

By which type of nuclear reaction is energy produced in a nuclear reactor?

EasyAtomic Nucleus01 Mark marks
Answer

In a nuclear reactor, energy is produced by a controlled nuclear fission chain reaction.

2.11

Match the items in the Left Column with the appropriate items in the Right Column: [1 × 4 = 4]

Left Column Right Column
2.11.1 Most electronegative element (a) Cu
2.11.2 Extracted from hematite (b) Cl
2.11.3 The element whose anion accelerates the rusting of iron (c) F
2.11.4 The metal present in a greater percentage in the alloy brass (d) Fe
EasyMetallurgy04 Mark marks
Answer

2.11.1 – (c)

2.11.2 – (d)

2.11.3 – (b)

2.11.4 – (a)

2.12

Which of the following compounds is a covalent compound?

Potassium chloride, Sodium bromide, Carbon tetrachloride

EasyIonic and Covalent Bond01 Mark marks
Answer

Carbon tetrachloride (CCl₄)

Explanation

Carbon tetrachloride is a covalent compound because carbon and chlorine atoms form bonds by sharing electrons.

Potassium chloride (KCl) and sodium bromide (NaBr) are ionic compounds.

2.13

Write the name of the electrolyte used for gold plating.

EasyElectrolysis01 Mark marks
Answer

Potassium aurocyanide [K[Au(CN)₂]] solution is used as the electrolyte for gold plating.

How is electricity conducted in an aqueous solution of an electrolyte during electrolysis?

EasyElectrolysis01 Mark marks
Answer

In an aqueous solution of an electrolyte, electricity is conducted by the movement of positive and negative ions (cations and anions) towards the respective electrodes.

2.14

Why cannot alternating current be used in electrolysis?

ModerateElectrolysis01 Mark marks
Answer

Alternating current (AC) cannot be used in electrolysis because its direction changes periodically. Hence, the electrodes continuously interchange their polarity and a continuous chemical reaction or deposition at a particular electrode cannot take place.

2.15

Write the formula of the black precipitate formed when H₂S gas is passed through an aqueous solution of lead nitrate.

EasyInorganic Chemistry01 Mark marks
Answer

PbS (Lead sulphide)

Explanation

When H₂S gas is passed through an aqueous solution of lead nitrate, a black precipitate of lead sulphide (PbS) is formed.

Pb(NO₃)₂ + H₂S → PbS↓ + 2HNO₃

Fill in the blank:

2NH₃ + CO₂ → ______ + H₂O

EasyInorganic Chemistry01 Mark marks
Answer

NH₂CONH₂ (Urea)

2.16

Write the chemical equation for the reaction between two gases to produce a solid substance.

ModerateInorganic Chemistry01 Mark marks
Answer

The reaction between ammonia gas (NH₃) and hydrogen chloride gas (HCl) produces solid ammonium chloride (NH₄Cl).

NH₃(g) + HCl(g) → NH₄Cl(s)

The product ammonium chloride is formed as a white solid.

2.17

Write the IUPAC name of the organic compound:

CH₃–CH(OH)–CH₃

EasyOrganic Chemistry01 Mark marks
Answer

Propan-2-ol

Explanation

The compound contains three carbon atoms and the –OH functional group is attached to the second carbon atom. Hence, its IUPAC name is propan-2-ol.

Write the structural formula of ethanoic acid.

EasyOrganic Chemistry01 Mark marks
Answer

The structural formula of ethanoic acid is:

Ethanoic acid

2.18

Write one use of PVC.

EasyOrganic Chemistry01 Mark marks
Answer

PVC (Polyvinyl Chloride) is used for making water pipes.

It is suitable for making pipes because it is durable, lightweight and resistant to corrosion.

Question 3 | Group C
Answer the following Questions (alternatives are to be noted):  [2 × 9 = 18]
3.1

What is the concept of sustainable development?

EasyConcerns about our Environment02 Mark marks
Answer

Sustainable development means development that meets the needs of the present generation without compromising the ability of future generations to meet their own needs.

It aims at maintaining a proper balance between:

  • Economic development
  • Conservation of natural resources
  • Protection of the environment
3.2

A fixed mass of gas kept at 0°C is heated. What will be the temperature of the gas when both its pressure and volume are doubled compared to the initial values?

ModerateBehaviour of Gases02 Mark marks
Answer

Initial temperature (T₁) = 0°C = 273 K

Let initial pressure = P₁ and initial volume = V₁

Final pressure (P₂) = 2P₁

Final volume (V₂) = 2V₁

From Combined Gas Law: \frac{\text{P₁V₁}}{\text{T₁}}=\frac{\text{P₂V₂}}{\text{T₂}}

⇒  \frac{\text{P₁V₁}}{273}=\frac{2\text{P₁}\times2\text{V₁}}{\text{T₂}}

⇒ T₂ = 4 × 273 = 1092 K

⇒ T₂ = 1092 − 273 = 819°C

Hence, the final temperature of the gas is 819°C.

A gas of mass 2 g occupies a volume of 820 ml at 7°C temperature and 2 atm pressure. Determine the molar mass of the gas. [R = 0.082 L atm mole⁻¹ K⁻¹]

ModerateBehaviour of Gases02 Mark marks
Answer

Mass of gas (m) = 2 g

Volume (V) = 820 ml = 0.820 L

Temperature (T) = 7°C = 280 K

Pressure (P) = 2 atm

Gas constant (R) = 0.082 L atm mol⁻¹ K⁻¹

From Ideal Gas Equation: PV = nRT

Number of moles (n) = \frac{\text{PV}}{\text{RT}}

= \frac{2\times0.820}{0.082\times280}

= 0.0714 mol

Molar mass (M) = \frac{\text{Mass}}{\text{Number of moles}}

= \frac{2}{0.0714}

= 28 g mol⁻¹

Hence, the molar mass of the gas is 28 g mol⁻¹.

3.3

Determine the speed of a light ray passing through a glass slab of refractive index 1.5. [c = 3 × 10⁵ m s⁻¹]

EasyLight – Reflection and Refraction02 Mark marks
Answer

Refractive index of glass (μ) = 1.5

Speed of light in vacuum (c) = 3 × 10⁵ m s⁻¹

Speed of light in glass (v) = ?

We know, μ = \frac{\text{c}}{\text{v}}

Therefore,

v = \frac{\text{c}}{\text{μ}}

= \frac{3\times10^5}{1.5}

= 2 × 10⁵ m s⁻¹

Hence, the speed of light in the glass slab is 2 × 10⁵ m s⁻¹.

A convex lens forms a 10 times magnified image of an object. If the length of the object is 5 cm, determine the length of the image.

ModerateLight – Reflection and Refraction02 Mark marks
Answer

Magnification (m) = 10

Height of object (h₁) = 5 cm

Height of image (h₂) = ?

We know,

m = \frac{\text{h₂}}{\text{h₁}}

Therefore,

h₂ = m × h₁

= 10 × 5

= 50 cm

Hence, the length of the image is 50 cm.

3.4

The length of a wire having a resistance of 15 ohms is stretched by 20%. If the volume of the wire remains constant after stretching and its cross-section remains uniform throughout, determine the new resistance of the wire

HardCurrent Electricity02 Mark marks
Answer

Initial resistance (R₁) = 15 Ω

Let initial length = L₁

After stretching by 20%,

Final Length (L₂) = L₁ + 20% of L₁ = 1.2L₁

Since the volume of the wire remains constant,

A₁L₁ = A₂L₂

Therefore,

A₂ = \frac{\text{A₁L₁}}{\text{L₂}}

= \frac{\text{A₁}}{1.2}

We know,

R = \frac{\text{ρL}}{\text{A}}

Therefore, \frac{\text{R₂}}{\text{R₁}}=\frac{\text{L₂A₁}}{\text{L₁A₂}}

= 1.2 × 1.2

= 1.44

R₂ = 1.44 × 15

= 21.6 Ω

Hence, the new resistance of the wire is 21.6 Ω.

3.5

Liquid hydrogen chloride is unable to conduct electricity, but molten sodium chloride is able to conduct electricity — explain

ModerateIonic and Covalent Bond02 Mark marks
Answer

Liquid hydrogen chloride (HCl) is a covalent compound and does not contain free ions in the liquid state. Therefore, it cannot conduct electricity.

On the other hand, molten sodium chloride (NaCl) contains freely moving Na⁺ and Cl⁻ ions. These ions carry electric charge through the molten salt. Therefore, molten NaCl conducts electricity.

Explain with an example of a suitable ionic compound that its ions do not obey the octet rule.

Moderate02 Mark marks
Answer

The octet rule is not obeyed by all ions. For example, lithium hydride (LiH) is an ionic compound.

Li → Li⁺ + e⁻

H + e⁻ → H⁻

The Li⁺ and H⁻ ions have only 2 electrons each in their outermost shell and attain a duplet configuration instead of an octet.

Thus, ions of some ionic compounds such as LiH attain a stable duplet configuration and do not obey the octet rule.

3.6

Give an example of a solid and a liquid covalent compound.

EasyIonic and Covalent Bond02 Mark marks
Answer

Solid covalent compound: Naphthalene (C₁₀H₈)

Liquid covalent compound: Carbon tetrachloride (CCl₄)

Both are covalent compounds in which atoms are bonded by the sharing of electrons.

3.7

Write the name of a gas that can be prepared using Kipp’s apparatus. Write the balanced chemical equation for the reaction of preparation of the gas. [1 + 1]

EasyInorganic Chemistry02 Mark marks
Answer

Hydrogen sulphide (H₂S) can be prepared using Kipp’s apparatus.

It is prepared by the reaction of iron sulphide (FeS) with dilute sulphuric acid (H₂SO₄).

FeS + H₂SO₄ → FeSO₄ + H₂S↑

Hence, the gas prepared is hydrogen sulphide (H₂S).

3.8

Why does a copper vessel turn green in open air?

ModerateMetallurgy02 Mark marks
Answer

Copper reacts slowly with moist air containing oxygen, carbon dioxide and water vapour and forms a green coating of basic copper carbonate [CuCO₃·Cu(OH)₂] on its surface.

Therefore, a copper vessel turns green when exposed to open air for a long time.

Write two reasons why curd and sour fruits are not kept in copper and brass vessels for a long time

EasyMetallurgy02 Mark marks
Answer

Curd and sour fruits contain acids. Therefore, they should not be kept in copper or brass vessels for a long time because:

  • The acids react with the metals present in the vessels and form metal salts.
  • These metal salts may be toxic and harmful to health, making the food unfit for consumption.
3.9

CH₃COOH is an organic compound but NaHCO₃ is not an organic compound; write one reason for each case.

ModerateOrganic Chemistry02 Mark marks
Answer

CH₃COOH (acetic acid) is an organic compound because it contains carbon bonded with hydrogen and possesses the characteristic –COOH functional group of organic carboxylic acids.

NaHCO₃ (sodium bicarbonate) is not an organic compound because it is an ionic salt containing the bicarbonate ion (HCO₃⁻) and is classified as an inorganic carbon compound.

Show with the help of the structural formula of ethylene that it is an unsaturated hydrocarbon.

EasyOrganic Chemistry02 Mark marks
Answer

Structural formula of ethylene (C₂H₄):

H₂C = CH₂

Ethylene contains a carbon-carbon double bond (C=C). Therefore, the valencies of carbon atoms are not fully saturated with hydrogen atoms.

Hence, ethylene is an unsaturated hydrocarbon.

Question 4 | Group D
Answer the following Questions (alternatives are to be noted): [3 × 12 = 36]
4.1

State and explain Charles’s law. Determine the value of absolute zero on the Celsius scale from Charles’s law. [1+2]

HardBehaviour of Gases03 Mark marks
Answer

Charles’s Law: At constant pressure, the volume of a fixed mass of gas increases or decreases by 1/273 of its volume at 0°C for every 1°C rise or fall in temperature.

If V₀ is the volume of a gas at 0°C, then its volume at t°C is:

Vt = V₀ \left(1+\frac{\text{t}}{273}\right)

or, Vt = \frac{\text{V₀}(273+\text{t})}{273}

Therefore, \frac{\text{Vₜ}}{273+\text{t}}=\frac{\text{V₀}}{273}

Hence, at constant pressure,

\frac{\text{V}}{\text{T}}=\text{Constant}

Determination of Absolute Zero

According to Charles’s law,

Vt = V₀ \left(1+\frac{\text{t}}{273}\right)

At absolute zero, the volume of an ideal gas theoretically becomes zero.

Therefore, 0 = V₀ \left(1+\frac{\text{t}}{273}\right)

or, 1 + \frac{\text{t}}{273} = 0

or, t = −273°C

Hence, the value of absolute zero on the Celsius scale is −273°C.

4.2

What mass of KClO₃ needs to be heated to produce the same amount of oxygen as is obtained by heating 216 g of HgO?

[Hg = 200, K = 39, Cl = 35.5, O = 16]

HardChemical Calculations03 Mark marks
Answer

(i) From HgO

Balanced equation: 2HgO → 2Hg + O₂

Molar mass of HgO = 200 + 16 = 216 g/mol

From the equation,

2 × 216 g HgO produces 32 g O₂

Therefore, 216 g HgO produces = \frac{32\times216}{2\times216} = 16 g O₂

Now,

Balanced equation for KClO₃:

2KClO₃ → 2KCl + 3O₂

Molar mass of KClO₃ = 39 + 35.5 + (16 × 3)

= 122.5 g/mol

From the equation,

2 × 122.5 g KClO₃ produces 3 × 32 g O₂

Therefore, mass of KClO₃ required to produce 16 g O₂

= \frac{2\times122.5\times16}{3\times32}

= 40.83 g

Hence, 40.83 g of KClO₃ must be heated.

Heating 200 g of a metallic carbonate produces 112 g of metallic oxide and a gaseous compound. The vapour density of the gaseous compound is 22. How many moles of the gaseous compound are produced in the reaction?

EasyChemical Calculations03 Mark marks
Answer

Mass of metallic carbonate = 200 g

Mass of metallic oxide = 112 g

Therefore, Mass of gaseous compound

= 200 − 112

= 88 g

Given, Vapour density = 22

Molar mass of gas = 2 × Vapour density

= 2 × 22

= 44 g/mol

Number of moles = \frac{\text{Mass}}{\text{Molar Mass}}

= \frac{88}{44}

= 2 mol

Hence, 2 moles of the gaseous compound are produced.

4.3

Explain the statement: “The coefficient of linear expansion of iron is 12 × 10⁻⁶ /°C”. Give an example of volume expansion of a liquid due to the application of heat. [2+1]

ModerateThermal phenomena03 Mark marks
Answer

The coefficient of linear expansion of iron is 12 × 10⁻⁶ /°C means that for every 1°C rise in temperature, a unit length of iron increases in length by 12 × 10⁻⁶ of its original length.

For example, if the initial length of an iron rod is 1 m, then for a rise of temperature of 1°C, increase in length will be:

ΔL = 12 × 10⁻⁶ m

Define the coefficient of apparent expansion and the coefficient of real expansion of a liquid. Write the relationship between them. [2+1]

ModerateThermal phenomena03 Mark marks
Answer

Coefficient of apparent expansion: The apparent increase in volume per unit original volume of a liquid for a rise in temperature of 1°C is called the coefficient of apparent expansion of the liquid.

Coefficient of real expansion: The actual increase in volume per unit original volume of a liquid for a rise in temperature of 1°C is called the coefficient of real expansion of the liquid.

The relationship is:

Coefficient of real expansion = Coefficient of apparent expansion + Coefficient of volume expansion of the vessel

or, γr = γa + γv

4.4

Establish the relationship between radius of curvature (r) and focal length (f) for a convex mirror. Write one use of a concave mirror. [2+1]

ModerateLight – Reflection and Refraction03 Mark marks
Answer

Establish the relationship between radius of curvature

Let P, F and C be the pole, focus and centre of curvature of the convex mirror.

According to the law of reflection, ∠MQC’ = ∠NQC’

Since MQ ∥ PC, ∠CQC’ = ∠FCQ

Therefore, ∠FCQ = ∠FQC

Hence, FC = FQ

For paraxial rays, FQ ≈ FP = f

Therefore, FC = FP = f

Now, CP = CF + FP = 2f

Since CP = r,

r = 2f or, f = \frac{\text{r}}{2}

Use of concave mirror: It is used as a reflector in vehicle headlights.

For the same angle of incidence, the angles of refraction in three different media A, B and C are 30°, 45° and 60° respectively. In which medium is the speed of light minimum and why? [3]

EasyLight – Reflection and Refraction03 Mark marks
Answer

For the same angle of incidence,

Angle of refraction in medium A = 30°

Angle of refraction in medium B = 45°

Angle of refraction in medium C = 60°

According to Snell’s law,

μ = \frac{\sin\text{i}}{\sin\text{r}}

Since the angle of incidence i is the same for all three media, the medium having the smallest angle of refraction has the highest refractive index.

Therefore,

μA > μB > μC

Also, v = \frac{\text{c}}{\text{μ}}

Thus, greater refractive index means lower speed of light.

Hence, the speed of light is minimum in medium A because it has the smallest angle of refraction (30°) and therefore the highest refractive index.

4.5

Write two causes of short-sightedness or myopia. Which type of lens is used to correct it? [2+1]

EasyLight – Reflection and Refraction03 Mark marks
Answer

Myopia may occur due to:

  1. Excessive curvature of the eye lens, which increases its converging power.
  2. Elongation of the eyeball, which causes the image of a distant object to form in front of the retina.

Correction- Myopia is corrected by using a concave lens of suitable focal length.

4.6

The cost per B.O.T unit of electrical energy is ₹6. Calculate the total cost of electricity used in a month of 30 days if ten 50 W bulbs are used for 10 hours daily. [3]

ModerateCurrent Electricity03 Mark marks
Answer

Number of bulbs = 10

Power of each bulb = 50 W

Total power (P) = 10 × 50 = 500 W = 0.5 kW

Time used per day = 10 hours

Total time in 30 days (t) = 10 × 30 = 300 hours

Electrical energy consumed = 0.5 × 300

= 150 kWh = 150 B.O.T units

Total cost = 150 × 6 (Cost per unit = ₹6)

= ₹900

Hence, the total cost of electricity for 30 days is ₹900.

When two conductors are connected in series, the equivalent resistance is 25 Ω, and when connected in parallel, the equivalent resistance is 6 Ω. Determine the resistance of each conductor.

HardCurrent Electricity03 Mark marks
Answer

Let the resistances be R₁ and R₂.

For series combination:

R₁ + R₂ = 25 Ω …(1)

For parallel combination: 6 = \frac{\text{R₁R₂}}{\text{R₁}+\text{R₂}}

Using (1),

6 = \frac{\text{R₁R₂}}{25}

Therefore,

R₁R₂ = 150 …(2)

From (1), R₂ = 25 − R₁

Putting in (2), R₁(25 − R₁) = 150

25R₁ − R₁² = 150

⇒ R₁² − 25R₁ + 150 = 0

⇒ R₁² − 15R₁ − 10R₁ + 150 = 0

⇒ R₁(R₁ − 15) − 10(R₁ − 15) = 0

⇒ (R₁ − 15)(R₁ − 10) = 0

⇒ R₁ = 15 Ω or 10 Ω

Therefore, R₁ = 10 Ω, R₂ = 15 Ω

4.7

Mention any two advantages of using alternating current over direct current. Why is hydroelectric power generation more environmentally friendly than thermal power generation? [1+2]

EasyCurrent Electricity03 Mark marks
Answer

Two advantages of AC over DC

  1. AC voltage can be easily increased or decreased using a transformer.
  2. AC can be transmitted over long distances with less power loss by transmitting it at high voltage.

Hydroelectric power is more environmentally friendly because:

  1. It uses flowing or stored water, which is a renewable source of energy.
  2. It does not involve the burning of fossil fuels and hence produces almost no smoke, CO₂ or other harmful gases during electricity generation.
4.8

Explain nuclear fission. Why is nuclear fission essential for nuclear fusion? [2+1]

ModerateAtomic Nucleus03 Mark marks
Answer

Nuclear Fission

The process in which a heavy atomic nucleus splits into two or more lighter nuclei, with the release of a large amount of energy and neutrons, is called nuclear fission.

For example:

²³⁵U + ¹n → ¹⁴¹Ba + ⁹²Kr + 3¹n + Energy

Nuclear fusion requires an extremely high temperature to occur. The large amount of heat produced by nuclear fission is used to provide this high temperature and initiate nuclear fusion.

4.9

What is meant by the electronegativity of an element? How does the electronegativity of Group 1 elements in the long periodic table change from top to bottom? [1+2]

EasyPeriodic Table03 Mark marks
Answer

Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons towards itself.

In Group 1, electronegativity decreases from top to bottom. This is because down the group the atomic size increases. The attraction of the nucleus for the shared pair of electrons decreases.

Hence, Li > Na > K > Rb > Cs

What is the important conclusion of Moseley’s experiment? What is the importance of this conclusion regarding the periodic table? [2+1]

ModeratePeriodic Table03 Mark marks
Answer

From Moseley’s experiment, it was concluded that the atomic number, and not the atomic mass, is the fundamental property of an element.

Therefore, the modern periodic law is based on atomic number: The physical and chemical properties of elements are periodic functions of their atomic numbers.

This removed the defects caused by arranging elements according to their atomic masses.

4.10

In the extraction of aluminium by electrolysis, what substances are present in the molten mixture besides pure alumina? What are used as the cathode and anode in this electrolysis? [2+1]

EasyMetallurgy03 Mark marks
Answer

Besides pure alumina (Al₂O₃), the molten mixture contains:

  1. Cryolite (Na₃AlF₆)
  2. Fluorspar (CaF₂)

In the electrolytic cell:

  • Cathode: Carbon lining of the iron tank
  • Anode: Graphite (carbon) rods
4.11

Write how nitric oxide is produced by the oxidation of ammonia with atmospheric oxygen, mentioning the name of the catalyst and the reaction conditions. Write the balanced chemical equation for the reaction. [2+1]

ModerateInorganic Chemistry03 Mark marks
Answer

In the Ostwald process, ammonia is oxidised by atmospheric oxygen by passing a mixture of ammonia and air over a wired mesh of platinum or platinum–rhodium catalyst at a temperature of 750–900°C (1023–1173 K).

Nitric oxide is formed according to the reaction:

4NH₃ + 5O₂ → 4NO + 6H₂O + Heat

Thus, nitric oxide (NO) is obtained by the catalytic oxidation of ammonia with atmospheric oxygen.

Catalyst: Platinum or platinum–rhodium wired mesh

Temperature: 750–900°C (1023–1173 K)

4.12

Write the balanced chemical equation for the addition reaction of hydrogen with acetylene and mention any two conditions for the reaction. [3]

EasyOrganic Chemistry03 Mark marks
Answer

Acetylene undergoes addition reaction with hydrogen to form ethane.

CH≡CH + H₂ {\overset{Ni}{\longrightarrow}}  CH₂=CH₂  + H₂ {\overset{Ni}{\longrightarrow}} CH₃–CH₃

Conditions:

  1. Nickel (Ni) is used as a catalyst.
  2. The reaction is carried out on heating.

Write the balanced chemical equation for the reaction between acetic acid and sodium bicarbonate. Between jute and polythene, which one is eco-friendly for packaging purposes and why? [1+2]

EasyOrganic Chemistry03 Mark marks
Answer

Acetic acid reacts with sodium bicarbonate to form sodium acetate, water and carbon dioxide.

CH₃COOH + NaHCO₃ → CH₃COONa + H₂O + CO₂↑

Jute is more eco-friendly than polythene for packaging because:

  1. Jute is biodegradable and decomposes naturally.
  2. Polythene is non-biodegradable and causes environmental pollution.
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