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Madhyamik Class 10 Physical Science Solved Paper 2026

Complete WBBSE Class X Physical Science 2026 question paper with accurate, step-by-step solutions.

WBBSEClass XPhysical Science202690 Marks3 h54 Questions

Question 1 of 54

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A

Question 1 · Group A

Multiple choice Questions. [1 × 15 = 15]

Question 1.1

1.1Concerns about our EnvironmentEasy1 Mark

Which of the following gases does not help in the depletion of the ozone layer?

(a) CFC

(b) NO

(c) CO₂

(d) NO₂

Answer

(c) CO₂

Explanation

Carbon dioxide (CO₂) is a greenhouse gas that contributes to global warming, but it does not directly take part in the depletion of the ozone layer.

Question 1.2

1.2Behaviour of GasesModerate1 Mark

The mass of 11.2 L of NH₃ gas at S.T.P. is:

[N = 14, H = 1]

(a) 17 g

(b) 8.5 g

(c) 34 g

(d) 11.2 g

Answer

(b) 8.5 g

Explanation

At S.T.P., 1 mole of any gas occupies 22.4 L.

Therefore, 11.2 L of NH₃ = \frac{11.2}{22.4} = 0.5 mol

Molar mass of NH₃ = 14 + (1 × 3) = 17 g/mol

Mass of 0.5 mol NH₃ = 0.5 × 17 = 8.5 g

Question 1.3

1.3Chemical CalculationsModerate1 Mark

According to the following chemical equation, what volume of oxygen at S.T.P. is required for the complete combustion of 5 moles of methane?

CH₄ + 2O₂ → CO₂ + 2H₂O

(a) 224 L

(b) 448 L

(c) 44.8 L

(d) 22.4 L

Answer

(a) 224 L

Explanation

CH₄ + 2O₂ → CO₂ + 2H₂O

From the balanced chemical equation,

1 mole of CH₄ requires 2 moles of O₂.

Therefore, 5 moles of CH₄ require = 5 × 2

= 10 moles of O₂

At S.T.P., 1 mole of any gas occupies 22.4 L.

Volume of 10 moles of O₂ = 10 × 22.4 = 224 L

Question 1.4

1.4Thermal phenomenaEasy1 Mark

The SI unit of thermal conductivity is:

(a) W m⁻¹ K⁻¹

(b) cal m⁻¹ °C⁻¹

(c) W m K⁻¹

(d) W m² K⁻¹

Answer

(a) W m⁻¹ K⁻¹

Explanation

The SI unit of thermal conductivity is watt per metre per kelvin (W m⁻¹ K⁻¹).

Thermal conductivity is defined as the amount of heat conducted per second through unit area of a material of unit thickness when the temperature difference between its two faces is 1 K.

Question 1.5

1.5Light – Reflection and RefractionEasy1 Mark

The least distance of distinct vision for a normal human eye is:

(a) 25 cm

(b) 100 cm

(c) Infinity

(d) 0 cm

Answer

(a) 25 cm

Explanation

The least distance of distinct vision (near point) for a normal human eye is 25 cm.

It is the minimum distance from the eye at which an object can be seen clearly and distinctly without strain.

Question 1.6

1.6Light – Reflection and RefractionEasy1 Mark

When a ray of light is incident normally on the surface of a glass slab, the angle of refraction will be:

(a) 0°

(b) 90°

(c) 180°

(d) 30°

Answer

(a) 0°

Explanation

When a ray of light is incident normally on the surface of a glass slab, the angle of incidence is 0°.

According to Snell’s law, the ray passes undeviated along the normal. Therefore, the angle of refraction is also 0°.

Question 1.7

1.7Current ElectricityEasy1 Mark

The total charge of how many electrons is equal to 1 coulomb?

(a) 1.6 × 10¹⁹

(b) 6.25 × 10¹⁰

(c) 6.25 × 10¹⁸

(d) 6.023 × 10²³

Answer

(c) 6.25 × 10¹⁸

Explanation

Charge of one electron = 1.6 × 10⁻¹⁹ C

Number of electrons corresponding to 1 C = \frac{1}{1.6 \times 10^{-19}}

= 6.25 × 10¹⁸

Question 1.8

1.8Current ElectricityEasy1 Mark

With increase in temperature, the resistance decreases in:

(a) Copper

(b) Nichrome

(c) Glass

(d) Silicon

Answer

(d) Silicon

Explanation

Silicon is a semiconductor. As its temperature increases, the number of free charge carriers also increases, causing its electrical resistance to decrease.

Question 1.9

1.9Atomic NucleusEasy1 Mark

If the mass of an electron is m, then the mass of a β-particle is:

(a) m

(b) 2m

(c) 3m

(d) 4m

Answer

(a) m

Explanation

A β-particle (β⁻) is a high-speed electron emitted from the nucleus during beta decay.

Therefore, the mass of a β-particle is equal to the mass of an electron.

Question 1.10

1.10Periodic TableEasy1 Mark

If the atomic number of an element is 19, in which group of the modern periodic table is the element placed?

(a) Group 1

(b) Group 2

(c) Group 18

(d) Group 9

Answer

(a) Group 1

Explanation

An element with atomic number 19 is Potassium (K).

Electronic configuration of potassium: 2, 8, 8, 1

Since it has one electron in its outermost shell, it belongs to Group 1 (Alkali Metals) of the modern periodic table.

Question 1.11

1.11Inorganic ChemistryEasy1 Mark

The substance used for drying ammonia gas is:

(a) CaCl₂

(b) CaO

(c) H₂SO₄

(d) P₂O₅

Answer

(b) CaO

Explanation

Quick lime (CaO) is used for drying ammonia gas (NH₃) because it absorbs moisture without reacting with ammonia.

Concentrated H₂SO₄ and P₂O₅ cannot be used because they react with ammonia.
Anhydrous CaCl₂ is also not suitable because it forms an addition compound with ammonia.

Question 1.12

1.12MetallurgyEasy1 Mark

Which of the following elements is not present in Duralumin?

(a) Al

(b) Zn

(c) Cu

(d) Mg

Answer

(b) Zn

Explanation

Duralumin is an alloy composed mainly of:

  • Aluminium (Al)
  • Copper (Cu)
  • Magnesium (Mg)
  • Manganese (Mn)

Zinc (Zn) is not a constituent of duralumin.

Question 1.13

1.13Inorganic ChemistryEasy1 Mark

What will be the colour of the solution formed when excess aqueous ammonia is added to aqueous copper sulphate solution?

(a) Yellow

(b) Orange

(c) Green

(d) Deep blue

Answer

(d) Deep blue

Explanation

When excess aqueous ammonia (NH₄OH) is added to copper sulphate (CuSO₄) solution, a deep blue solution is formed due to the formation of the tetraammine copper(II) complex.

Question 1.14

1.14ElectrolysisEasy1 Mark

Which of the following has the highest electrical conductivity?

(a) Aqueous solution of sugar

(b) Pure water

(c) Liquid hydrogen chloride

(d) None of these

Answer

(d) None of these

Explanation

  • Aqueous sugar solution: Sugar is a covalent compound that dissolves as neutral molecules, not ions.
  • Pure water: Contains almost no free ions (extremely weak self-ionization).
  • Liquid HCl: Pure covalent liquid without free ions (it only ionizes and conducts when dissolved in water).

Question 1.15

1.15Organic ChemistryEasy1 Mark

The value of the H-C-H bond angle in a methane molecule is –

(a) 109°28′

(b) 108°29′

(c) 100°

(d) 180°

Answer

(a) 109°28′

Explanation:

Methane (CH4) has a tetrahedral structure with four identical single bonds around the central carbon atom. In a regular tetrahedron, the bond angle between any two bonds is 109°28′ (or about 109.5°).

B

Question 2 · Group B

Answer the following Questions (alternatives are to be noted): [1 × 21 = 21]

Question 2.1

2.1Concerns about our EnvironmentEasy1 Mark

Write the name of the main component of biogas.

Answer

Methane (CH₄)

Explanation

Biogas mainly contains methane, along with smaller amounts of gases such as carbon dioxide.

OR
ORConcerns about our EnvironmentEasy1 Mark

Write the name of a gas involved in our breathing process whose increase in the atmosphere causes global warming.

Answer

Carbon dioxide (CO₂)

Explanation

Carbon dioxide is involved in the breathing/respiration cycle and is also a greenhouse gas. An increase in its concentration in the atmosphere contributes to global warming.

Question 2.2

2.2Concerns about our EnvironmentEasy1 Mark

What is meant by saying the calorific value of natural gas is 50 kJ/g?

Answer

The calorific value of natural gas is 50 kJ/g means that 50 kJ of heat energy is produced when 1 g of natural gas is completely burnt in oxygen.

Question 2.3

2.3Behaviour of GasesEasy1 Mark

State whether the following statement is true or false: Equal volumes of all gases under the same conditions of temperature and pressure contain an equal number of atoms.

Answer

False

Explanation

According to Avogadro’s Law, equal volumes of all gases at the same temperature and pressure contain an equal number of molecules, not necessarily an equal number of atoms.

Question 2.4

2.4Behaviour of GasesEasy1 Mark

Write the SI unit of the ideal gas constant.

Answer

The SI unit of the ideal gas constant R is: J mol⁻¹ K⁻¹

Question 2.5

2.5Thermal phenomenaEasy1 Mark

State whether the following statement is true or false: The real expansion of a liquid depends on the expansion of the vessel in which the liquid is kept.

Answer

False

Explanation

The real expansion of a liquid is independent of the expansion of the vessel. It is the actual increase in the volume of the liquid due to heating.

OR
ORThermal phenomenaEasy1 Mark

If the length and cross-sectional area of a conductor remain unchanged, what is the relationship between the thermal resistance and thermal conductivity of that conductor?

Answer

Thermal resistance, Rt = \frac{\text{L}}{\text{K}\text{A}}

Since the length L and cross-sectional area A remain constant,

Rt ∝ \frac{1}{\text{K}}

Therefore, thermal resistance is inversely proportional to thermal conductivity.

Question 2.6

2.6Light – Reflection and RefractionEasy1 Mark

Which color of light undergoes the minimum scattering?

Answer

Red light

Explanation

Red light has the longest wavelength among the colours of visible light. According to Rayleigh’s law, the intensity of scattering is inversely proportional to the fourth power of wavelength:

Scattering ∝ \frac{1}{\text{λ}^4}

Therefore, red light undergoes the minimum scattering.

Question 2.7

2.7Light – Reflection and RefractionEasy1 Mark

Give an example of a natural spectrum.

Answer

Rainbow

Explanation

A rainbow is an example of a natural spectrum. It is formed due to the dispersion of sunlight by tiny water droplets present in the atmosphere.

Question 2.8

2.8Current ElectricityEasy1 Mark

Write the name of a device where electrical energy is converted into mechanical energy.

Answer

Electric motor

Question 2.9

2.9Current ElectricityEasy1 Mark

How much work has to be done to move an electric charge against a potential difference?

Answer

The work required to move a charge Q through a potential difference V is QV joule.

Question 2.10

2.10Atomic NucleusEasy1 Mark

Write the name of the positively charged radioactive particle.

Answer

Alpha (α) particle.

OR
ORAtomic NucleusEasy1 Mark

By which type of nuclear reaction is energy produced in a nuclear reactor?

Answer

In a nuclear reactor, energy is produced by a controlled nuclear fission chain reaction.

Question 2.11

2.11MetallurgyEasy4 Marks

Match the items in the Left Column with the appropriate items in the Right Column: [1 × 4 = 4]

Left Column Right Column
2.11.1 Most electronegative element (a) Cu
2.11.2 Extracted from hematite (b) Cl
2.11.3 The element whose anion accelerates the rusting of iron (c) F
2.11.4 The metal present in a greater percentage in the alloy brass (d) Fe
Answer

2.11.1 – (c)

2.11.2 – (d)

2.11.3 – (b)

2.11.4 – (a)

Question 2.12

2.12Ionic and Covalent BondEasy1 Mark

Which of the following compounds is a covalent compound?

Potassium chloride, Sodium bromide, Carbon tetrachloride

Answer

Carbon tetrachloride (CCl₄)

Explanation

Carbon tetrachloride is a covalent compound because carbon and chlorine atoms form bonds by sharing electrons.

Potassium chloride (KCl) and sodium bromide (NaBr) are ionic compounds.

Question 2.13

2.13ElectrolysisEasy1 Mark

Write the name of the electrolyte used for gold plating.

Answer

Potassium aurocyanide [K[Au(CN)₂]] solution is used as the electrolyte for gold plating.

OR
ORElectrolysisEasy1 Mark

How is electricity conducted in an aqueous solution of an electrolyte during electrolysis?

Answer

In an aqueous solution of an electrolyte, electricity is conducted by the movement of positive and negative ions (cations and anions) towards the respective electrodes.

Question 2.14

2.14ElectrolysisModerate1 Mark

Why cannot alternating current be used in electrolysis?

Answer

Alternating current (AC) cannot be used in electrolysis because its direction changes periodically. Hence, the electrodes continuously interchange their polarity and a continuous chemical reaction or deposition at a particular electrode cannot take place.

Question 2.15

2.15Inorganic ChemistryEasy1 Mark

Write the formula of the black precipitate formed when H₂S gas is passed through an aqueous solution of lead nitrate.

Answer

PbS (Lead sulphide)

Explanation

When H₂S gas is passed through an aqueous solution of lead nitrate, a black precipitate of lead sulphide (PbS) is formed.

Pb(NO₃)₂ + H₂S → PbS↓ + 2HNO₃

OR
ORInorganic ChemistryEasy1 Mark

Fill in the blank:

2NH₃ + CO₂ → ______ + H₂O

Answer

NH₂CONH₂ (Urea)

Question 2.16

2.16Inorganic ChemistryModerate1 Mark

Write the chemical equation for the reaction between two gases to produce a solid substance.

Answer

The reaction between ammonia gas (NH₃) and hydrogen chloride gas (HCl) produces solid ammonium chloride (NH₄Cl).

NH₃(g) + HCl(g) → NH₄Cl(s)

The product ammonium chloride is formed as a white solid.

Question 2.17

2.17Organic ChemistryEasy1 Mark

Write the IUPAC name of the organic compound:

CH₃–CH(OH)–CH₃

Answer

Propan-2-ol

Explanation

The compound contains three carbon atoms and the –OH functional group is attached to the second carbon atom. Hence, its IUPAC name is propan-2-ol.

OR
OROrganic ChemistryEasy1 Mark

Write the structural formula of ethanoic acid.

Answer

The structural formula of ethanoic acid is:

Ethanoic acid

Question 2.18

2.18Organic ChemistryEasy1 Mark

Write one use of PVC.

Answer

PVC (Polyvinyl Chloride) is used for making water pipes.

It is suitable for making pipes because it is durable, lightweight and resistant to corrosion.

C

Question 3 · Group C

Answer the following Questions (alternatives are to be noted):  [2 × 9 = 18]

Question 3.1

3.1Concerns about our EnvironmentEasy2 Marks

What is the concept of sustainable development?

Answer

Sustainable development means development that meets the needs of the present generation without compromising the ability of future generations to meet their own needs.

It aims at maintaining a proper balance between:

  • Economic development
  • Conservation of natural resources
  • Protection of the environment

Question 3.2

3.2Behaviour of GasesModerate2 Marks

A fixed mass of gas kept at 0°C is heated. What will be the temperature of the gas when both its pressure and volume are doubled compared to the initial values?

Answer

Initial temperature (T₁) = 0°C = 273 K

Let initial pressure = P₁ and initial volume = V₁

Final pressure (P₂) = 2P₁

Final volume (V₂) = 2V₁

From Combined Gas Law: \frac{\text{P₁V₁}}{\text{T₁}}=\frac{\text{P₂V₂}}{\text{T₂}}

⇒  \frac{\text{P₁V₁}}{273}=\frac{2\text{P₁}\times2\text{V₁}}{\text{T₂}}

⇒ T₂ = 4 × 273 = 1092 K

⇒ T₂ = 1092 − 273 = 819°C

Hence, the final temperature of the gas is 819°C.

OR
ORBehaviour of GasesModerate2 Marks

A gas of mass 2 g occupies a volume of 820 ml at 7°C temperature and 2 atm pressure. Determine the molar mass of the gas. [R = 0.082 L atm mole⁻¹ K⁻¹]

Answer

Mass of gas (m) = 2 g

Volume (V) = 820 ml = 0.820 L

Temperature (T) = 7°C = 280 K

Pressure (P) = 2 atm

Gas constant (R) = 0.082 L atm mol⁻¹ K⁻¹

From Ideal Gas Equation: PV = nRT

Number of moles (n) = \frac{\text{PV}}{\text{RT}}

= \frac{2\times0.820}{0.082\times280}

= 0.0714 mol

Molar mass (M) = \frac{\text{Mass}}{\text{Number of moles}}

= \frac{2}{0.0714}

= 28 g mol⁻¹

Hence, the molar mass of the gas is 28 g mol⁻¹.

Question 3.3

3.3Light – Reflection and RefractionEasy2 Marks

Determine the speed of a light ray passing through a glass slab of refractive index 1.5. [c = 3 × 10⁵ m s⁻¹]

Answer

Refractive index of glass (μ) = 1.5

Speed of light in vacuum (c) = 3 × 10⁵ m s⁻¹

Speed of light in glass (v) = ?

We know, μ = \frac{\text{c}}{\text{v}}

Therefore,

v = \frac{\text{c}}{\text{μ}}

= \frac{3\times10^5}{1.5}

= 2 × 10⁵ m s⁻¹

Hence, the speed of light in the glass slab is 2 × 10⁵ m s⁻¹.

OR
ORLight – Reflection and RefractionModerate2 Marks

A convex lens forms a 10 times magnified image of an object. If the length of the object is 5 cm, determine the length of the image.

Answer

Magnification (m) = 10

Height of object (h₁) = 5 cm

Height of image (h₂) = ?

We know,

m = \frac{\text{h₂}}{\text{h₁}}

Therefore,

h₂ = m × h₁

= 10 × 5

= 50 cm

Hence, the length of the image is 50 cm.

Question 3.4

3.4Current ElectricityHard2 Marks

The length of a wire having a resistance of 15 ohms is stretched by 20%. If the volume of the wire remains constant after stretching and its cross-section remains uniform throughout, determine the new resistance of the wire

Answer

Initial resistance (R₁) = 15 Ω

Let initial length = L₁

After stretching by 20%,

Final Length (L₂) = L₁ + 20% of L₁ = 1.2L₁

Since the volume of the wire remains constant,

A₁L₁ = A₂L₂

Therefore,

A₂ = \frac{\text{A₁L₁}}{\text{L₂}}

= \frac{\text{A₁}}{1.2}

We know,

R = \frac{\text{ρL}}{\text{A}}

Therefore, \frac{\text{R₂}}{\text{R₁}}=\frac{\text{L₂A₁}}{\text{L₁A₂}}

= 1.2 × 1.2

= 1.44

R₂ = 1.44 × 15

= 21.6 Ω

Hence, the new resistance of the wire is 21.6 Ω.

Question 3.5

3.5Ionic and Covalent BondModerate2 Marks

Liquid hydrogen chloride is unable to conduct electricity, but molten sodium chloride is able to conduct electricity — explain

Answer

Liquid hydrogen chloride (HCl) is a covalent compound and does not contain free ions in the liquid state. Therefore, it cannot conduct electricity.

On the other hand, molten sodium chloride (NaCl) contains freely moving Na⁺ and Cl⁻ ions. These ions carry electric charge through the molten salt. Therefore, molten NaCl conducts electricity.

OR
ORModerate2 Marks

Explain with an example of a suitable ionic compound that its ions do not obey the octet rule.

Answer

The octet rule is not obeyed by all ions. For example, lithium hydride (LiH) is an ionic compound.

Li → Li⁺ + e⁻

H + e⁻ → H⁻

The Li⁺ and H⁻ ions have only 2 electrons each in their outermost shell and attain a duplet configuration instead of an octet.

Thus, ions of some ionic compounds such as LiH attain a stable duplet configuration and do not obey the octet rule.

Question 3.6

3.6Ionic and Covalent BondEasy2 Marks

Give an example of a solid and a liquid covalent compound.

Answer

Solid covalent compound: Naphthalene (C₁₀H₈)

Liquid covalent compound: Carbon tetrachloride (CCl₄)

Both are covalent compounds in which atoms are bonded by the sharing of electrons.

Question 3.7

3.7Inorganic ChemistryEasy2 Marks

Write the name of a gas that can be prepared using Kipp’s apparatus. Write the balanced chemical equation for the reaction of preparation of the gas. [1 + 1]

Answer

Hydrogen sulphide (H₂S) can be prepared using Kipp’s apparatus.

It is prepared by the reaction of iron sulphide (FeS) with dilute sulphuric acid (H₂SO₄).

FeS + H₂SO₄ → FeSO₄ + H₂S↑

Hence, the gas prepared is hydrogen sulphide (H₂S).

Question 3.8

3.8MetallurgyModerate2 Marks

Why does a copper vessel turn green in open air?

Answer

Copper reacts slowly with moist air containing oxygen, carbon dioxide and water vapour and forms a green coating of basic copper carbonate [CuCO₃·Cu(OH)₂] on its surface.

Therefore, a copper vessel turns green when exposed to open air for a long time.

OR
ORMetallurgyEasy2 Marks

Write two reasons why curd and sour fruits are not kept in copper and brass vessels for a long time

Answer

Curd and sour fruits contain acids. Therefore, they should not be kept in copper or brass vessels for a long time because:

  • The acids react with the metals present in the vessels and form metal salts.
  • These metal salts may be toxic and harmful to health, making the food unfit for consumption.

Question 3.9

3.9Organic ChemistryModerate2 Marks

CH₃COOH is an organic compound but NaHCO₃ is not an organic compound; write one reason for each case.

Answer

CH₃COOH (acetic acid) is an organic compound because it contains carbon bonded with hydrogen and possesses the characteristic –COOH functional group of organic carboxylic acids.

NaHCO₃ (sodium bicarbonate) is not an organic compound because it is an ionic salt containing the bicarbonate ion (HCO₃⁻) and is classified as an inorganic carbon compound.

OR
OROrganic ChemistryEasy2 Marks

Show with the help of the structural formula of ethylene that it is an unsaturated hydrocarbon.

Answer

Structural formula of ethylene (C₂H₄):

H₂C = CH₂

Ethylene contains a carbon-carbon double bond (C=C). Therefore, the valencies of carbon atoms are not fully saturated with hydrogen atoms.

Hence, ethylene is an unsaturated hydrocarbon.

D

Question 4 · Group D

Answer the following Questions (alternatives are to be noted): [3 × 12 = 36]

Question 4.1

4.1Behaviour of GasesHard3 Marks

State and explain Charles’s law. Determine the value of absolute zero on the Celsius scale from Charles’s law. [1+2]

Answer

Charles’s Law: At constant pressure, the volume of a fixed mass of gas increases or decreases by 1/273 of its volume at 0°C for every 1°C rise or fall in temperature.

If V₀ is the volume of a gas at 0°C, then its volume at t°C is:

Vt = V₀ \left(1+\frac{\text{t}}{273}\right)

or, Vt = \frac{\text{V₀}(273+\text{t})}{273}

Therefore, \frac{\text{Vₜ}}{273+\text{t}}=\frac{\text{V₀}}{273}

Hence, at constant pressure,

\frac{\text{V}}{\text{T}}=\text{Constant}

Determination of Absolute Zero

According to Charles’s law,

Vt = V₀ \left(1+\frac{\text{t}}{273}\right)

At absolute zero, the volume of an ideal gas theoretically becomes zero.

Therefore, 0 = V₀ \left(1+\frac{\text{t}}{273}\right)

or, 1 + \frac{\text{t}}{273} = 0

or, t = −273°C

Hence, the value of absolute zero on the Celsius scale is −273°C.

Question 4.2

4.2Chemical CalculationsHard3 Marks

What mass of KClO₃ needs to be heated to produce the same amount of oxygen as is obtained by heating 216 g of HgO?

[Hg = 200, K = 39, Cl = 35.5, O = 16]

Answer

(i) From HgO

Balanced equation: 2HgO → 2Hg + O₂

Molar mass of HgO = 200 + 16 = 216 g/mol

From the equation,

2 × 216 g HgO produces 32 g O₂

Therefore, 216 g HgO produces = \frac{32\times216}{2\times216} = 16 g O₂

Now,

Balanced equation for KClO₃:

2KClO₃ → 2KCl + 3O₂

Molar mass of KClO₃ = 39 + 35.5 + (16 × 3)

= 122.5 g/mol

From the equation,

2 × 122.5 g KClO₃ produces 3 × 32 g O₂

Therefore, mass of KClO₃ required to produce 16 g O₂

= \frac{2\times122.5\times16}{3\times32}

= 40.83 g

Hence, 40.83 g of KClO₃ must be heated.

OR
ORChemical CalculationsEasy3 Marks

Heating 200 g of a metallic carbonate produces 112 g of metallic oxide and a gaseous compound. The vapour density of the gaseous compound is 22. How many moles of the gaseous compound are produced in the reaction?

Answer

Mass of metallic carbonate = 200 g

Mass of metallic oxide = 112 g

Therefore, Mass of gaseous compound

= 200 − 112

= 88 g

Given, Vapour density = 22

Molar mass of gas = 2 × Vapour density

= 2 × 22

= 44 g/mol

Number of moles = \frac{\text{Mass}}{\text{Molar Mass}}

= \frac{88}{44}

= 2 mol

Hence, 2 moles of the gaseous compound are produced.

Question 4.3

4.3Thermal phenomenaModerate3 Marks

Explain the statement: “The coefficient of linear expansion of iron is 12 × 10⁻⁶ /°C”. Give an example of volume expansion of a liquid due to the application of heat. [2+1]

Answer

The coefficient of linear expansion of iron is 12 × 10⁻⁶ /°C means that for every 1°C rise in temperature, a unit length of iron increases in length by 12 × 10⁻⁶ of its original length.

For example, if the initial length of an iron rod is 1 m, then for a rise of temperature of 1°C, increase in length will be:

ΔL = 12 × 10⁻⁶ m

OR
ORThermal phenomenaModerate3 Marks

Define the coefficient of apparent expansion and the coefficient of real expansion of a liquid. Write the relationship between them. [2+1]

Answer

Coefficient of apparent expansion: The apparent increase in volume per unit original volume of a liquid for a rise in temperature of 1°C is called the coefficient of apparent expansion of the liquid.

Coefficient of real expansion: The actual increase in volume per unit original volume of a liquid for a rise in temperature of 1°C is called the coefficient of real expansion of the liquid.

The relationship is:

Coefficient of real expansion = Coefficient of apparent expansion + Coefficient of volume expansion of the vessel

or, γr = γa + γv

Question 4.4

4.4Light – Reflection and RefractionModerate3 Marks

Establish the relationship between radius of curvature (r) and focal length (f) for a convex mirror. Write one use of a concave mirror. [2+1]

Answer

Establish the relationship between radius of curvature

Let P, F and C be the pole, focus and centre of curvature of the convex mirror.

According to the law of reflection, ∠MQC’ = ∠NQC’

Since MQ ∥ PC, ∠CQC’ = ∠FCQ

Therefore, ∠FCQ = ∠FQC

Hence, FC = FQ

For paraxial rays, FQ ≈ FP = f

Therefore, FC = FP = f

Now, CP = CF + FP = 2f

Since CP = r,

r = 2f or, f = \frac{\text{r}}{2}

Use of concave mirror: It is used as a reflector in vehicle headlights.

OR
ORLight – Reflection and RefractionEasy3 Marks

For the same angle of incidence, the angles of refraction in three different media A, B and C are 30°, 45° and 60° respectively. In which medium is the speed of light minimum and why? [3]

Answer

For the same angle of incidence,

Angle of refraction in medium A = 30°

Angle of refraction in medium B = 45°

Angle of refraction in medium C = 60°

According to Snell’s law,

μ = \frac{\sin\text{i}}{\sin\text{r}}

Since the angle of incidence i is the same for all three media, the medium having the smallest angle of refraction has the highest refractive index.

Therefore,

μA > μB > μC

Also, v = \frac{\text{c}}{\text{μ}}

Thus, greater refractive index means lower speed of light.

Hence, the speed of light is minimum in medium A because it has the smallest angle of refraction (30°) and therefore the highest refractive index.

Question 4.5

4.5Light – Reflection and RefractionEasy3 Marks

Write two causes of short-sightedness or myopia. Which type of lens is used to correct it? [2+1]

Answer

Myopia may occur due to:

  1. Excessive curvature of the eye lens, which increases its converging power.
  2. Elongation of the eyeball, which causes the image of a distant object to form in front of the retina.

Correction- Myopia is corrected by using a concave lens of suitable focal length.

Question 4.6

4.6Current ElectricityModerate3 Marks

The cost per B.O.T unit of electrical energy is ₹6. Calculate the total cost of electricity used in a month of 30 days if ten 50 W bulbs are used for 10 hours daily. [3]

Answer

Number of bulbs = 10

Power of each bulb = 50 W

Total power (P) = 10 × 50 = 500 W = 0.5 kW

Time used per day = 10 hours

Total time in 30 days (t) = 10 × 30 = 300 hours

Electrical energy consumed = 0.5 × 300

= 150 kWh = 150 B.O.T units

Total cost = 150 × 6 (Cost per unit = ₹6)

= ₹900

Hence, the total cost of electricity for 30 days is ₹900.

OR
ORCurrent ElectricityHard3 Marks

When two conductors are connected in series, the equivalent resistance is 25 Ω, and when connected in parallel, the equivalent resistance is 6 Ω. Determine the resistance of each conductor.

Answer

Let the resistances be R₁ and R₂.

For series combination:

R₁ + R₂ = 25 Ω …(1)

For parallel combination: 6 = \frac{\text{R₁R₂}}{\text{R₁}+\text{R₂}}

Using (1),

6 = \frac{\text{R₁R₂}}{25}

Therefore,

R₁R₂ = 150 …(2)

From (1), R₂ = 25 − R₁

Putting in (2), R₁(25 − R₁) = 150

25R₁ − R₁² = 150

⇒ R₁² − 25R₁ + 150 = 0

⇒ R₁² − 15R₁ − 10R₁ + 150 = 0

⇒ R₁(R₁ − 15) − 10(R₁ − 15) = 0

⇒ (R₁ − 15)(R₁ − 10) = 0

⇒ R₁ = 15 Ω or 10 Ω

Therefore, R₁ = 10 Ω, R₂ = 15 Ω

Question 4.7

4.7Current ElectricityEasy3 Marks

Mention any two advantages of using alternating current over direct current. Why is hydroelectric power generation more environmentally friendly than thermal power generation? [1+2]

Answer

Two advantages of AC over DC

  1. AC voltage can be easily increased or decreased using a transformer.
  2. AC can be transmitted over long distances with less power loss by transmitting it at high voltage.

Hydroelectric power is more environmentally friendly because:

  1. It uses flowing or stored water, which is a renewable source of energy.
  2. It does not involve the burning of fossil fuels and hence produces almost no smoke, CO₂ or other harmful gases during electricity generation.

Question 4.8

4.8Atomic NucleusModerate3 Marks

Explain nuclear fission. Why is nuclear fission essential for nuclear fusion? [2+1]

Answer

Nuclear Fission

The process in which a heavy atomic nucleus splits into two or more lighter nuclei, with the release of a large amount of energy and neutrons, is called nuclear fission.

For example:

²³⁵U + ¹n → ¹⁴¹Ba + ⁹²Kr + 3¹n + Energy

Nuclear fusion requires an extremely high temperature to occur. The large amount of heat produced by nuclear fission is used to provide this high temperature and initiate nuclear fusion.

Question 4.9

4.9Periodic TableEasy3 Marks

What is meant by the electronegativity of an element? How does the electronegativity of Group 1 elements in the long periodic table change from top to bottom? [1+2]

Answer

Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons towards itself.

In Group 1, electronegativity decreases from top to bottom. This is because down the group the atomic size increases. The attraction of the nucleus for the shared pair of electrons decreases.

Hence, Li > Na > K > Rb > Cs

OR
ORPeriodic TableModerate3 Marks

What is the important conclusion of Moseley’s experiment? What is the importance of this conclusion regarding the periodic table? [2+1]

Answer

From Moseley’s experiment, it was concluded that the atomic number, and not the atomic mass, is the fundamental property of an element.

Therefore, the modern periodic law is based on atomic number: The physical and chemical properties of elements are periodic functions of their atomic numbers.

This removed the defects caused by arranging elements according to their atomic masses.

Question 4.10

4.10MetallurgyEasy3 Marks

In the extraction of aluminium by electrolysis, what substances are present in the molten mixture besides pure alumina? What are used as the cathode and anode in this electrolysis? [2+1]

Answer

Besides pure alumina (Al₂O₃), the molten mixture contains:

  1. Cryolite (Na₃AlF₆)
  2. Fluorspar (CaF₂)

In the electrolytic cell:

  • Cathode: Carbon lining of the iron tank
  • Anode: Graphite (carbon) rods

Question 4.11

4.11Inorganic ChemistryModerate3 Marks

Write how nitric oxide is produced by the oxidation of ammonia with atmospheric oxygen, mentioning the name of the catalyst and the reaction conditions. Write the balanced chemical equation for the reaction. [2+1]

Answer

In the Ostwald process, ammonia is oxidised by atmospheric oxygen by passing a mixture of ammonia and air over a wired mesh of platinum or platinum–rhodium catalyst at a temperature of 750–900°C (1023–1173 K).

Nitric oxide is formed according to the reaction:

4NH₃ + 5O₂ → 4NO + 6H₂O + Heat

Thus, nitric oxide (NO) is obtained by the catalytic oxidation of ammonia with atmospheric oxygen.

Catalyst: Platinum or platinum–rhodium wired mesh

Temperature: 750–900°C (1023–1173 K)

Question 4.12

4.12Organic ChemistryEasy3 Marks

Write the balanced chemical equation for the addition reaction of hydrogen with acetylene and mention any two conditions for the reaction. [3]

Answer

Acetylene undergoes addition reaction with hydrogen to form ethane.

CH≡CH + H₂ {\overset{Ni}{\longrightarrow}}  CH₂=CH₂  + H₂ {\overset{Ni}{\longrightarrow}} CH₃–CH₃

Conditions:

  1. Nickel (Ni) is used as a catalyst.
  2. The reaction is carried out on heating.
OR
OROrganic ChemistryEasy3 Marks

Write the balanced chemical equation for the reaction between acetic acid and sodium bicarbonate. Between jute and polythene, which one is eco-friendly for packaging purposes and why? [1+2]

Answer

Acetic acid reacts with sodium bicarbonate to form sodium acetate, water and carbon dioxide.

CH₃COOH + NaHCO₃ → CH₃COONa + H₂O + CO₂↑

Jute is more eco-friendly than polythene for packaging because:

  1. Jute is biodegradable and decomposes naturally.
  2. Polythene is non-biodegradable and causes environmental pollution.